**Newton Raphson Method MATLAB code :**

**Introduction to Iterative methods:**

There are a number of iterative methods like Jacobi method, Gauss–Seidel method that have been tried and used successfully in various problem situations. All these methods typically generate a sequence of estimates of the solution which is expected to converge to the true solution.

Newton Raphson method is also one of the iterative method which is used to find the roots of given expression.

**Newton Raphson Method with MATLAB code:**

If point x0 is close to the root α, then tangent line to the graph of f(x) at x0 is a good approximation the f(x) near α. So root of the tangent line, where line cuts the X-axis; x1 is the better approximation to α than x0 is.

Slope of the tangent =

Repeating process, we obtain a better approximation,

Continue in this way. If *xn *is the current estimate, then the next estimate *xn*+1 is given by

if x0 is sufficiently close to α, xn→α as n→∞.

**Limitations of Newton Raphson method:**

- If initial guess is too far away from the required root, the process may converge to some other root.
- Division by zero may occur if f’(xi) is zero or very close to zero.
- A particular value in the iteration sequence may repeat, resulting in an infinite loop.

**Newton Raphson MATLAB program : **

% Newton Raphson Method

clear all

close all

clc

% Change here for different functions

f=@(x) cos(x)-3*x+1

%this is the derivative of the above function

df=@(x) -sin(x)-3

% Change lower limit ‘a’ and upper limit ‘b’

a=0; b=1;

x=a;

for i=1:1:100

x1=x-(f(x)/df(x));

x=x1;

end

sol=x;

fprintf(‘Approximate Root is %.15f’,sol)

a=0;b=1;

x=a;

er(5)=0;

for i=1:1:5

x1=x-(f(x)/df(x));

x=x1;

er(i)=x1-sol;

end

plot(er)

xlabel(‘Number of iterations’)

ylabel(‘Error’)

title(‘Error Vs. Number of iterations’)

**ANSWER :**

f =

@(x)cos(x)-3*x+1

df =

@(x)-sin(x)-3

Approximate Root is 0.6071016481031231

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